We want to gather data created by multiple Workers.
First we create a Queue:
sink = Queue.new
Then 16 workers all generating a random number and pushing it into sink:
(1..16).to_a.map do
Thread.new do
sink << rand(1..100)
end
end.map(&:join)
And to get the data, convert a Queue to an Array:
data = [].tap { |a| a << sink.pop until sink.empty? }
We want to process data in parallel.
Let's populate source with some data:
source = Queue.new
data = (1..100)
data.each { |e| source << e }
Then create some workers to process data:
(1..16).to_a.map do
Thread.new do
until source.empty?
item = source.pop
sleep 0.5
puts "Processed: #{item}"
end
end
end.map(&:join)
We want to process data in parallel and push it down the line to be processed by other workers.
Since Workers both consume and produce data we have to create two queues:
first_input_source = Queue.new
first_output_sink = Queue.new
100.times { |i| first_input_source << i }
First wave of workers read an item from first_input_source
, process the item, and write results in first_output_sink
:
(1..16).to_a.map do
Thread.new do
loop do
item = first_input_source.pop
first_output_source << item ** 2
first_output_source << item ** 3
end
end
end
Second wave of workers uses first_output_sink
as its input source and reads, process then writes to another output sink:
second_input_source = first_output_sink
second_output_sink = Queue.new
(1..32).to_a.map do
Thread.new do
loop do
item = second_input_source.pop
second_output_sink << item * 2
second_output_sink << item * 3
end
end
end
Now second_output_sink
is the sink, let's convert it to an array:
sleep 5 # workaround in place of synchronization
sink = second_output_sink
[].tap { |a| a << sink.pop until sink.empty? }
q = Queue.new
q << "any object including another queue"
# or
q.push :data
#push
never blocksq = Queue.new
q << :data
q.pop #=> :data
#pop
will block until there is some data available.#pop
can be used for synchronization.syncer = Queue.new
a = Thread.new do
syncer.pop
puts "this happens at end"
end
b = Thread.new do
puts "this happens first"
STDOUT.flush
syncer << :ok
end
[a, b].map(&:join)
q = Queue.new
q << 1
q << 2
a = Array.new
a << q.pop until q.empty?
Or a one liner:
[].tap { |array| array < queue.pop until queue.empty? }
Let's start by defining and populating two queues:
q1 = Queue.new
q2 = Queue.new
(1..100).each { |e| q1 << e }
(101..200).each { |e| q2 << e }
We should create another queue and push data from other threads into it:
merged = Queue.new
[q1, q2].map do |q|
Thread.new do
loop do
merged << q.pop
end
end
end
If you know you can completely consume both queues (consumption speed is higher than production, you won't run out of RAM) there is a simpler approach:
merged = Queue.new
merged << q1.pop until q1.empty?
merged << q2.pop until q2.empty?