Good resources for learning about concurrent and parallel programming in Haskell are:
Haskell supports many forms of concurrency and the most obvious being forking a thread using forkIO.
The function forkIO :: IO () -> IO ThreadId takes an IO action and returns its ThreadId, meanwhile the action will be run in the background.
We can demonstrate this quite succinctly using ghci:
Prelude Control.Concurrent> forkIO $ (print . sum) [1..100000000]
ThreadId 290
Prelude Control.Concurrent> forkIO $ print "hi!"
"hi!"
-- some time later....
Prelude Control.Concurrent> 50000005000000
Both actions will run in the background, and the second is almost guaranteed to finish before the last!
It is very easy to pass information between threads using the MVar a type and its accompanying functions in Control.Concurrent:
newEmptyMVar :: IO (MVar a) -- creates a new MVar anewMVar :: a -> IO (MVar a) -- creates a new MVar with the given valuetakeMVar :: MVar a -> IO a -- retrieves the value from the given MVar, or blocks until one is availableputMVar :: MVar a -> a -> IO () -- puts the given value in the MVar, or blocks until it's emptyLet's sum the numbers from 1 to 100 million in a thread and wait on the result:
import Control.Concurrent
main = do
m <- newEmptyMVar
forkIO $ putMVar m $ sum [1..10000000]
print =<< takeMVar m -- takeMVar will block 'til m is non-empty!
A more complex demonstration might be to take user input and sum in the background while waiting for more input:
main2 = loop
where
loop = do
m <- newEmptyMVar
n <- getLine
putStrLn "Calculating. Please wait"
-- In another thread, parse the user input and sum
forkIO $ putMVar m $ sum [1..(read n :: Int)]
-- In another thread, wait 'til the sum's complete then print it
forkIO $ print =<< takeMVar m
loop
As stated earlier, if you call takeMVar and the MVar is empty, it blocks until another thread puts something into the MVar, which could result in a Dining Philosophers Problem. The same thing happens with putMVar: if it's full, it'll block 'til it's empty!
Take the following function:
concurrent ma mb = do
a <- takeMVar ma
b <- takeMVar mb
putMVar ma a
putMVar mb b
We run the the two functions with some MVars
concurrent ma mb -- new thread 1
concurrent mb ma -- new thread 2
What could happen is that:
ma and blocks mamb and thus blocks mbNow Thread 1 cannot read mb as Thread 2 has blocked it, and Thread 2 cannot read ma as Thread 1 has blocked it. A classic deadlock!
Another powerful & mature concurrency tool in Haskell is Software Transactional Memory, which allows for multiple threads to write to a single variable of type TVar a in an atomic manner.
TVar a is the main type associated with the STM monad and stands for transactional variable. They're used much like MVar but within the STM monad through the following functions:
atomically :: STM a -> IO aPerform a series of STM actions atomically.
readTVar :: TVar a -> STM aRead the TVar's value, e.g.:
value <- readTVar t
writeTVar :: TVar a -> a -> STM ()Write a value to the given TVar.
t <- newTVar Nothing writeTVar t (Just "Hello")
This example is taken from the Haskell Wiki:
import Control.Monad
import Control.Concurrent
import Control.Concurrent.STM
main = do
-- Initialise a new TVar
shared <- atomically $ newTVar 0
-- Read the value
before <- atomRead shared
putStrLn $ "Before: " ++ show before
forkIO $ 25 `timesDo` (dispVar shared >> milliSleep 20)
forkIO $ 10 `timesDo` (appV ((+) 2) shared >> milliSleep 50)
forkIO $ 20 `timesDo` (appV pred shared >> milliSleep 25)
milliSleep 800
after <- atomRead shared
putStrLn $ "After: " ++ show after
where timesDo = replicateM_
milliSleep = threadDelay . (*) 1000
atomRead = atomically . readTVar
dispVar x = atomRead x >>= print
appV fn x = atomically $ readTVar x >>= writeTVar x . fn