Good resources for learning about concurrent and parallel programming in Haskell are:
Haskell supports many forms of concurrency and the most obvious being forking a thread using forkIO
.
The function forkIO :: IO () -> IO ThreadId
takes an IO
action and returns its ThreadId
, meanwhile the action will be run in the background.
We can demonstrate this quite succinctly using ghci
:
Prelude Control.Concurrent> forkIO $ (print . sum) [1..100000000]
ThreadId 290
Prelude Control.Concurrent> forkIO $ print "hi!"
"hi!"
-- some time later....
Prelude Control.Concurrent> 50000005000000
Both actions will run in the background, and the second is almost guaranteed to finish before the last!
It is very easy to pass information between threads using the MVar a
type and its accompanying functions in Control.Concurrent
:
newEmptyMVar :: IO (MVar a)
-- creates a new MVar a
newMVar :: a -> IO (MVar a)
-- creates a new MVar
with the given valuetakeMVar :: MVar a -> IO a
-- retrieves the value from the given MVar
, or blocks until one is availableputMVar :: MVar a -> a -> IO ()
-- puts the given value in the MVar
, or blocks until it's emptyLet's sum the numbers from 1 to 100 million in a thread and wait on the result:
import Control.Concurrent
main = do
m <- newEmptyMVar
forkIO $ putMVar m $ sum [1..10000000]
print =<< takeMVar m -- takeMVar will block 'til m is non-empty!
A more complex demonstration might be to take user input and sum in the background while waiting for more input:
main2 = loop
where
loop = do
m <- newEmptyMVar
n <- getLine
putStrLn "Calculating. Please wait"
-- In another thread, parse the user input and sum
forkIO $ putMVar m $ sum [1..(read n :: Int)]
-- In another thread, wait 'til the sum's complete then print it
forkIO $ print =<< takeMVar m
loop
As stated earlier, if you call takeMVar
and the MVar
is empty, it blocks until another thread puts something into the MVar
, which could result in a Dining Philosophers Problem. The same thing happens with putMVar
: if it's full, it'll block 'til it's empty!
Take the following function:
concurrent ma mb = do
a <- takeMVar ma
b <- takeMVar mb
putMVar ma a
putMVar mb b
We run the the two functions with some MVar
s
concurrent ma mb -- new thread 1
concurrent mb ma -- new thread 2
What could happen is that:
ma
and blocks ma
mb
and thus blocks mb
Now Thread 1 cannot read mb
as Thread 2 has blocked it, and Thread 2 cannot read ma
as Thread 1 has blocked it. A classic deadlock!
Another powerful & mature concurrency tool in Haskell is Software Transactional Memory, which allows for multiple threads to write to a single variable of type TVar a
in an atomic manner.
TVar a
is the main type associated with the STM
monad and stands for transactional variable. They're used much like MVar
but within the STM
monad through the following functions:
atomically :: STM a -> IO a
Perform a series of STM actions atomically.
readTVar :: TVar a -> STM a
Read the TVar
's value, e.g.:
value <- readTVar t
writeTVar :: TVar a -> a -> STM ()
Write a value to the given TVar
.
t <- newTVar Nothing writeTVar t (Just "Hello")
This example is taken from the Haskell Wiki:
import Control.Monad import Control.Concurrent import Control.Concurrent.STM main = do -- Initialise a new TVar shared <- atomically $ newTVar 0 -- Read the value before <- atomRead shared putStrLn $ "Before: " ++ show before forkIO $ 25 `timesDo` (dispVar shared >> milliSleep 20) forkIO $ 10 `timesDo` (appV ((+) 2) shared >> milliSleep 50) forkIO $ 20 `timesDo` (appV pred shared >> milliSleep 25) milliSleep 800 after <- atomRead shared putStrLn $ "After: " ++ show after where timesDo = replicateM_ milliSleep = threadDelay . (*) 1000 atomRead = atomically . readTVar dispVar x = atomRead x >>= print appV fn x = atomically $ readTVar x >>= writeTVar x . fn